# How to read “(x+y)^z” in Japanese?

How to read "(x+y)^z" in Japanese?

Is this correct?

かっこ ｘ たす ｙ かっこーとじ の ｚ じ

Kakko x tasu y kakko-toji no z jo

• – naruto Jun 1 '20 at 3:31
• Um, your TL is describing an entirely different equation... how did you get to that...? – Darius Jahandarie Jun 1 '20 at 3:49
• 2乗(にじょ) is "square" (`^2`), not exponentiation in general (`^n`). – naruto Jun 1 '20 at 4:44
• @naruto yes, z is an exponent. – AYA Jun 1 '20 at 5:14
• @DariusJahandarie Thank you for pointing that. I'm sorry for the mistake. I mistakenly copied the other translation from my document. I edited the question now. – AYA Jun 1 '20 at 5:16

As described in the question above, there are several approaches to read this. The most simple approach is to read each symbol one by one. This `^` symbol can be read ハット, キャレット or 累乗【るいじょう】.

かっこ エックス たす ワイ かっことじ るいじょう ゼット

More naturally, the expression xn can be read as "xのn乗" (エックス の エヌ じょう; "x to the power of n-th"). With this, you can read it like this:

かっこ エックス たす ワイ かっことじ の ゼット じょう

If you omit かっこ/かっことじ and say it like this:

エックス たす ワイ の ゼット じょう

...it may be taken as x + yz rather than (x + y)z. This may be okay if everyone is actually seeing the expression on a screen or a blackboard.

You can avoid this ambiguity by using 和【わ】:

エックス と ワイ の わ の ゼット じょう
(literally, "x-and-y's sum, to the z-th power")

Note that にじょう is "to the second" or "square" (x2), not n-th power in general (xn).