How to read "(x+y)^z" in Japanese?

Is this correct?

かっこ x たす y かっこーとじ の z じ

Kakko x tasu y kakko-toji no z jo

  • Related: japanese.stackexchange.com/q/56962/5010
    – naruto
    Commented Jun 1, 2020 at 3:31
  • Um, your TL is describing an entirely different equation... how did you get to that...? Commented Jun 1, 2020 at 3:49
  • 2乗(にじょ) is "square" (^2), not exponentiation in general (^n).
    – naruto
    Commented Jun 1, 2020 at 4:44
  • @naruto yes, z is an exponent.
    – AYA
    Commented Jun 1, 2020 at 5:14
  • @DariusJahandarie Thank you for pointing that. I'm sorry for the mistake. I mistakenly copied the other translation from my document. I edited the question now.
    – AYA
    Commented Jun 1, 2020 at 5:16

1 Answer 1


Please read this first: Standard mathematical operations, expressed in Japanese

As described in the question above, there are several approaches to read this. The most simple approach is to read each symbol one by one. This ^ symbol can be read ハット, キャレット or 累乗【るいじょう】.

かっこ エックス たす ワイ かっことじ るいじょう ゼット

More naturally, the expression xn can be read as "xのn乗" (エックス の エヌ じょう; "x to the power of n-th"). With this, you can read it like this:

かっこ エックス たす ワイ かっことじ の ゼット じょう

If you omit かっこ/かっことじ and say it like this:

エックス たす ワイ の ゼット じょう

...it may be taken as x + yz rather than (x + y)z. This may be okay if everyone is actually seeing the expression on a screen or a blackboard.

You can avoid this ambiguity by using 和【わ】:

エックス と ワイ の わ の ゼット じょう
(literally, "x-and-y's sum, to the z-th power")

Note that にじょう is "to the second" or "square" (x2), not n-th power in general (xn).

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